4s^2-10s=-6

Solution for 4s^2-10s=-6 equation:

4s^2-10s=-6

We move all terms to the left:

4s^2-10s-(-6)=0

We add all the numbers together, and all the variables

4s^2-10s+6=0

a = 4; b = -10; c = +6;
Δ = b2-4ac
Δ = -102-4·4·6
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2}{2*4}=\frac{8}{8}
=1
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2}{2*4}=\frac{12}{8}
=1+1/2
$